Spring Gun Horizontal Launch

← Back to Problems
Work and Energy Beginner mechanical energy and conservation Spring

Source: High school physics (Chinese)

Problem Sets:

work/energy basic

Problem

A spring in a spring gun has a spring constant $k = 80$ N/m. The trigger holds the spring compressed by 5 cm. A 10 g bullet is placed in the barrel against the spring. The barrel is horizontal.

Find the speed of the bullet as it leaves the muzzle.
$v = 2\sqrt{5}$ m/s

The mechanical energy of the bullet-spring system is conserved. The initial elastic potential energy of the compressed spring is converted into the kinetic energy of the bullet.

$$E_{initial} = E_{final}$$ $$U_{el,i} = K_f$$ $$\frac{1}{2}kx^2 = \frac{1}{2}mv^2$$

Solving for the velocity $v$:

$$v = x \sqrt{\frac{k}{m}}$$

Substitute the given values, with $m = 10 \text{ g} = 0.01 \text{ kg}$ and $x = 5 \text{ cm} = 0.05 \text{ m}$:

$$v = 0.05 \text{ m} \sqrt{\frac{80 \text{ N/m}}{0.01 \text{ kg}}} = \sqrt{20} \text{ m/s}$$