Ladder Network with Self-Similar Termination

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Electric Circuits Intermediate Ohm's Law

Source: High school physics (Chinese)

Problem

A ladder network connects terminals $A$ (top-left) and $B$ (bottom-left). Each cell of the ladder consists of a top horizontal resistor of value $R$, a bottom horizontal resistor of value $R$, and a vertical resistor (between the top and bottom rails) of value $R$. The network has an arbitrary number of cells. The rightmost vertical resistor is $R_x$ (unknown) rather than $R$.

  1. For what value of $R_x$ is the total resistance between $A$ and $B$ independent of the number of cells?
  2. What is this total resistance?
Problem image
$R_x = (\sqrt{3} - 1) R \approx 0.732 R$; $R_{AB} = (\sqrt{3} + 1) R \approx 2.732 R$.

Let $R^*$ be the equivalent resistance between the top and bottom nodes at the right edge of cell $k$ (including the vertical at position $k$ and everything to its right). For self-similarity (independence of cell count), $R^*$ must satisfy:

$$R^* = R \parallel (2R + R^*) = \dfrac{R(2R + R^*)}{3R + R^*}.$$

Cross-multiplying: $R^*(3R + R^*) = R(2R + R^*)$, giving

$$(R^*)^2 + 2R\,R^* - 2R^2 = 0.$$

Taking the positive root: $R^* = R(\sqrt{3} - 1)$.

To anchor the network so this self-similar value holds at the right end, we set the rightmost vertical to be $R_x = R^* = R(\sqrt{3} - 1)$.

Total resistance: $R_{AB} = 2R + R^* = R(\sqrt{3} + 1)$.