For a parallel-plate capacitor with a dielectric:

$$C = \dfrac{\varepsilon_r \varepsilon_0 A}{d},$$

where $A = \pi r^2$ is the plate area, $d$ the separation, and $\varepsilon_0 = 8.85 \times 10^{-12}$ F/m.

Plate area: $A = \pi (0.030)^2 = 9\pi \times 10^{-4}\ \mathrm{m^2} \approx 2.83 \times 10^{-3}\ \mathrm{m^2}.$

Capacitance:

$$C = \dfrac{6.0 \times 8.85 \times 10^{-12} \times 2.83 \times 10^{-3}}{2.0 \times 10^{-3}} \approx 7.5 \times 10^{-11}\ \mathrm{F}.$$